Jawab:
B.5[tex]\sqrt{5}[/tex]
Penjelasan dengan langkah-langkah:
gunakan teorema Pythagoras
DE=[tex]\sqrt{5^{2} +10^{2} } \\[/tex]
DE=[tex]\sqrt{25+100}=\sqrt{125}=\sqrt{25}\sqrt{5} =5\sqrt{5} (b)[/tex]
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Jawab:
B.5[tex]\sqrt{5}[/tex]
Penjelasan dengan langkah-langkah:
gunakan teorema Pythagoras
DE=[tex]\sqrt{5^{2} +10^{2} } \\[/tex]
DE=[tex]\sqrt{25+100}=\sqrt{125}=\sqrt{25}\sqrt{5} =5\sqrt{5} (b)[/tex]