Jawaban:
[tex]1. \: {x}^{2} + 7x + 6 = 0 \\ d = {b}^{2} - 4ac \\ d = {7}^{2} - 4.(1).(6) \\ \\ 2. \: {x}^{2} - 4x - 12 = 0 \\ d = {b}^{2} - 4ac \\ d = {4}^{2} - 4.(1).(12) \\ \\ 3. \: {x}^{2} - 8x + 16 = 0 \\ d = {b}^{2} - 4ac \\ d = {8}^{2} - 4.(1).(16) \\ \\ pemfaktorannya \\ 1. \: {x}^{2} + 7x + 6 = 0 \\ (x + 1)(x + 6) = 0 \\ x = - 1 \: atau \: x = - 6 \\ \\ 2. \: {x}^{2} - 4x - 12 = 0 \\ (x - 6)(x + 2) = 0 \\ x = 6 \: atau \: x = - 2 \\ \\ 3. \: {x}^{2} - 8x + 16 = 0 \\ (x - 4)(x - 4) = 0 \\ x = 4 \: atau \: x = 4[/tex]
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Verified answer
Jawaban:
[tex]1. \: {x}^{2} + 7x + 6 = 0 \\ d = {b}^{2} - 4ac \\ d = {7}^{2} - 4.(1).(6) \\ \\ 2. \: {x}^{2} - 4x - 12 = 0 \\ d = {b}^{2} - 4ac \\ d = {4}^{2} - 4.(1).(12) \\ \\ 3. \: {x}^{2} - 8x + 16 = 0 \\ d = {b}^{2} - 4ac \\ d = {8}^{2} - 4.(1).(16) \\ \\ pemfaktorannya \\ 1. \: {x}^{2} + 7x + 6 = 0 \\ (x + 1)(x + 6) = 0 \\ x = - 1 \: atau \: x = - 6 \\ \\ 2. \: {x}^{2} - 4x - 12 = 0 \\ (x - 6)(x + 2) = 0 \\ x = 6 \: atau \: x = - 2 \\ \\ 3. \: {x}^{2} - 8x + 16 = 0 \\ (x - 4)(x - 4) = 0 \\ x = 4 \: atau \: x = 4[/tex]