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Verified answer
Mapel : MatematikaKelas : X SMA
Bab : Vektor
Pembahasan :
12|| Salah soal masa a tegak lurus a
13||
a . b = |a| |b| Cos β
[9 -3 6] [3 5 -2] = √[9² + (-3)² + 6²] √[3² + 5² + (-2)²] = Cos β
9.3 + (-3).5 + 6(-2) = √126 √38 Cos β
27 - 15 - 12 = 6√133 Cos β
0 = 6√133 Cos β
Cos β = 0
Cos β = Cos 90°
β = 90°
Opsi A.