D
Penjelasan dengan langkah-langkah:
m = (y2-y1)/(x2-x1)
= (12-8)/(4-2)
= 4/2
= 2
persamaan dg m = 2 dan lewat (2,8)
y - 8 = 2(x - 2)
y - 8 = 2x - 4
y - 8 - 2x + 4 = 0
y - 2x - 4 = 0
titik yang dilalui (2,8) dan (4,12)
.
[tex] \tt \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
[tex] \tt \frac{y - 8}{12 - 8} = \frac{x - 2}{4 - 2} [/tex]
[tex] \tt \frac{y - 8}{4} = \frac{x - 2}{2} [/tex]
2(y - 8) = 4(x - 2)
y - 2x - 8 + 4 = 0
Jawaban D.
@BeruangGemoy :•
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D
Penjelasan dengan langkah-langkah:
m = (y2-y1)/(x2-x1)
= (12-8)/(4-2)
= 4/2
= 2
persamaan dg m = 2 dan lewat (2,8)
y - 8 = 2(x - 2)
y - 8 = 2x - 4
y - 8 - 2x + 4 = 0
y - 2x - 4 = 0
Verified answer
titik yang dilalui (2,8) dan (4,12)
.
[tex] \tt \frac{y - y1}{y2 - y1} = \frac{x - x1}{x2 - x1} [/tex]
[tex] \tt \frac{y - 8}{12 - 8} = \frac{x - 2}{4 - 2} [/tex]
[tex] \tt \frac{y - 8}{4} = \frac{x - 2}{2} [/tex]
2(y - 8) = 4(x - 2)
y - 8 = 2(x - 2)
y - 8 = 2x - 4
y - 2x - 8 + 4 = 0
y - 2x - 4 = 0
Jawaban D.
@BeruangGemoy :•