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f(2) = a(2) + b = 3
2a + b = 3
f(-3) = a(-3) + b = -13
-3a + b = -13
a. eliminasi b dengan mengurangi pers 1 dan 2
2a + b = 3
-3a + b = -13
----------------- -
5a = 16
a = 16/5
a = 3 1/5
substitusikan a = 16/5 ke pers 1
2(16/5) + b = 3
32/ 5 + b = 15/5
b = 15/5 - 32/5
b = -17/5
b = -3 2/5
Jadi, nilai a = 16/5 dan b = -17/5
b. -a + b
= -16/5 + (-17/5)
= -33/5
= -6 3/5
c. 2a + 3b