Question

TOLONG BANTU JAWAB YA KA​

Answer 1

2. <COB = 3x⁰, <BOA = ( 2x - 5 )⁰

<COB + <BOA = 180⁰( sudut berpelurus )

3x⁰ + ( 2x - 5 )⁰ = 180⁰

5x - 5⁰ = 180⁰

5x = 180⁰ + 5⁰

5x = 185⁰

x = 185⁰/5 = 37⁰

<COB = 3x⁰ = 3.37⁰ = 111⁰

3. <ATB = <DTC( sudut bertolak belakang )

( 23 + a )⁰ = 77⁰

a = 77⁰ - 23⁰

a = 54⁰

<ATB = ( 23 + a )⁰ = 23 + 54 = 77⁰

4. <COB = ( 4x + 6 )⁰, <BOA = 2x⁰

<COB + <BOA = 90⁰( sudut berpenyiku )

( 4x + 6 )⁰ + 2x⁰ = 90⁰

6x + 6⁰ = 90⁰

6x = 90⁰ - 6⁰

6x = 84⁰

x = 84⁰/6 = 14⁰

<COB = ( 4x + 6 )⁰

= ( 4.14⁰ + 6 )⁰

= 56 + 6 = 62⁰