Trigonometri
rumus jumlah
cos A + cos B = 2 cos 1/2 (A+B) cos 1/2 (A - B)
*
i) cos 6x + cos 2x = 2 cos 1/2 (6x+2x) cos 1/2(6x -2x)
cos 6x + cos 2x = 2 cos 1/2 (8x) cos 1/2 (4x)
cos 6x + cos 2x = 2 cos 4x cos 2x
ii) cos 6x + cos 2x = 2 { 2 cos² 2x - 1) (cos 2x)
cos 6x + cos 2x = 2 ( 2 cos³ 2x - cos 2x)
cos 6x + cos 2x = 4 cos³ 2x - 2cos 2x
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Verified answer
Trigonometri
rumus jumlah
cos A + cos B = 2 cos 1/2 (A+B) cos 1/2 (A - B)
*
i) cos 6x + cos 2x = 2 cos 1/2 (6x+2x) cos 1/2(6x -2x)
cos 6x + cos 2x = 2 cos 1/2 (8x) cos 1/2 (4x)
cos 6x + cos 2x = 2 cos 4x cos 2x
ii) cos 6x + cos 2x = 2 { 2 cos² 2x - 1) (cos 2x)
cos 6x + cos 2x = 2 ( 2 cos³ 2x - cos 2x)
cos 6x + cos 2x = 4 cos³ 2x - 2cos 2x