Question

Tolong bantu jawab soal lingkaran nomor 2​

Answer 1

2.Tegak lurus : m1.m2 = -1

3y + x = 4

3y = -x+4

y = -1/3 x + 4/3

m1 = -1/3

m1 . mgs = -1

(-1/3) . mgs = -1

mgs = 3

(x-2)²+(y-4)² = 10

r² = 10

r = √10

Persamaannya adalah :

y - 4 = 3(x-2) ± 10

y = 3x - 6 + 4 ± 10

y = 3x - 2 ± 10

y = 3x+8 atau y = 3x - 12