Jawab:
limit tak tentu
Penjelasan dengan langkah-langkah:
lim(x-> 0) [ sin² x - cos x + 1 ] / [ x tan x ]
.
*cos x = 1 - 2 sin² ¹/₂ x.
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Jawab:
limit tak tentu
Penjelasan dengan langkah-langkah:
lim(x-> 0) [ sin² x - cos x + 1 ] / [ x tan x ]
.
*cos x = 1 - 2 sin² ¹/₂ x.