Jawab:
limit trigonometri bentuk takj tentu
Penjelasan dengan langkah-langkah:
lim (x-> 1) [ (x² -1 ) 2 (x -1) ] / [ - 2 sin² (x - 1) ] =
.
= lim (x-> 1) [2 (x-1 ) ( x+1) (x -1) ] / [ - 2 sin² (x - 1) ]
= lim (x-> 1) [2 (x-1 )² ( x+1)] / [ - 2 sin² (x - 1) ]
= lim (x-> 1) [2 (x-1 )²/ -2 sin² ( x -1) ] . lim(x-> 1) (x +1)
= lim(x-> 1) - 1 ( x+1)
x= 1
L = - 1 (1+1)
L= - 2
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Jawab:
limit trigonometri bentuk takj tentu
Penjelasan dengan langkah-langkah:
lim (x-> 1) [ (x² -1 ) 2 (x -1) ] / [ - 2 sin² (x - 1) ] =
.
= lim (x-> 1) [2 (x-1 ) ( x+1) (x -1) ] / [ - 2 sin² (x - 1) ]
= lim (x-> 1) [2 (x-1 )² ( x+1)] / [ - 2 sin² (x - 1) ]
= lim (x-> 1) [2 (x-1 )²/ -2 sin² ( x -1) ] . lim(x-> 1) (x +1)
= lim(x-> 1) - 1 ( x+1)
x= 1
L = - 1 (1+1)
L= - 2