Question

Tolong bantu jawab soal ini buat dikumpulin pliss​

Answer 1

Jawaban:

Solution:

(a) The bomb free fell for a distance h. From h= 1/2 gt², we find that it takes t = √(2h/g)

for the bomb to reach the target.

(b) The horizontal velocity of the bomb is always V . Thus D = V t = V √(2h/g) .

(c) The vertical velocity of the bomb before striking the target is Vvert = tg = √2hg. The

speed of the bomb before striking the target is √(V²vert + V²)= √(2gh + V 2).

(d) Since the bomb and the airplane have the same horizontal velocity, when bomb striks

target, the airplane is right above the target.