[tex]diketahui \\ \pi = 3,14 \\ r = 10 \: cm \div 2 = 5 \: cm\\ s = 13 \: cm \\ \\ ditanya \\ luas \: selimut \: kerucut \\ \\ dijawab \\ luas \: selimut \: kerucut \\ \pi \times r \times s \\ 3,14 \times 5 \: cm \times 13 \: cm \\ 204,1 \: {cm}^{2} \: (a)[/tex]
LSK :
= πRS
= π(10/2(13)
= 3,14(5(13)
= 3,14(65)
= 204,1 CM² (A)
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[tex]diketahui \\ \pi = 3,14 \\ r = 10 \: cm \div 2 = 5 \: cm\\ s = 13 \: cm \\ \\ ditanya \\ luas \: selimut \: kerucut \\ \\ dijawab \\ luas \: selimut \: kerucut \\ \pi \times r \times s \\ 3,14 \times 5 \: cm \times 13 \: cm \\ 204,1 \: {cm}^{2} \: (a)[/tex]
LSK :
= πRS
= π(10/2(13)
= 3,14(5(13)
= 3,14(65)
= 204,1 CM² (A)