Question

Tolong bantu jawab plss

Answer 1

Nilai yang ditunjukkan

[tex] \frac{tc - tb}{td - tb} = \frac{tx - tb}{td - tb} \\ \\ \frac{40 - 0}{100 - 0 } = \frac{x - ( - 20)}{160 - ( - 20)} \\ \\ \frac{40}{100} = \frac{x + 20}{160 + 20} \\ \\ \frac{2}{5} = \frac{x + 20}{180} \\ \\ 5(x + 20) = 2(180) \\ 5x + 100 = 360 \\ 5x = 360 - 100 \\ 5x = 260 \\ x = \frac{260}{5} \\ x = 52°x[/tex]