√32-½√8+√18
=√16.2-½√4.2+√9.2
=4√2-√2+3√2
=(4-1+3)√2
=6√2(c.)
Semoga bermanfaat
Materi : Bentuk Akar dan Pangkat
√32 - ½√8 + √18
---
32 = 2⁵
8 = 2³
18 = 2 × 3²
√2⁵ - ½√2³ + √[ 2 × 3² ]
= √[ 2⁴ . 2 ] - ½√[ 2² . 2 ] + √[ 3² . 2 ]
= 2⁴/²√2 - [ ½ × 2²/² ]√2 + 3²/²√2
= 2²√2 - [ ½ . 2 ]√2 + 3√2
= 4√2 - 1√2 + 3√2
= ( 4 - 1 + 3 )√2
= ( 3 + 3 )√2
= 6√2 { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Penyelesaian
√32-½√8+√18
=√16.2-½√4.2+√9.2
=4√2-√2+3√2
=(4-1+3)√2
=6√2(c.)
Semoga bermanfaat
Materi : Bentuk Akar dan Pangkat
√32 - ½√8 + √18
---
32 = 2⁵
8 = 2³
18 = 2 × 3²
---
√2⁵ - ½√2³ + √[ 2 × 3² ]
= √[ 2⁴ . 2 ] - ½√[ 2² . 2 ] + √[ 3² . 2 ]
= 2⁴/²√2 - [ ½ × 2²/² ]√2 + 3²/²√2
= 2²√2 - [ ½ . 2 ]√2 + 3√2
= 4√2 - 1√2 + 3√2
= ( 4 - 1 + 3 )√2
= ( 3 + 3 )√2
= 6√2 { c. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]