Question

tolong bantu jawab, pakai cara yaa makasihh....​

Answer 1

Jawaban:

No 1.

[tex] \sf \sqrt{3} × \sqrt{8} [/tex]

[tex] \sf = \sqrt{(3 × 8) }[/tex]

[tex] \sf = \sqrt{24} [/tex]

[tex] \sf = \sqrt{(4 × 6) }[/tex]

[tex] \sf = \red{ 2\sqrt{6}}[/tex]

[tex] \: [/tex]

No 2.

[tex] \sf 2\sqrt{8} × \sqrt{3} [/tex]

[tex] \sf = 2\sqrt{(8 × 3)} [/tex]

[tex] \sf = 2\sqrt{(24) }[/tex]

[tex] \sf = 2\sqrt{(4 × 6)} [/tex]

[tex] \sf = 2(2\sqrt{6}) [/tex]

[tex] \sf = \red{4\sqrt{6}}[/tex]

[tex] \: [/tex]

No 3.

[tex] \sf \sqrt{300} : \sqrt{6 }[/tex]

[tex] \sf = \sqrt{ (300 : 6)}[/tex]

[tex] \sf = \sqrt{(50)}[/tex]

[tex] \sf = \sqrt{(25 × 2)}[/tex]

[tex] \sf = \red{5\sqrt{2}}[/tex]

[tex] \: [/tex]

No 4.

[tex] \sf \sqrt{108} + \sqrt{75}- \sqrt{147 }[/tex]

[tex] \sf = \sqrt{(36 × 3)} + \sqrt{(25 × 3)} - \sqrt{(49 × 3)}[/tex]

[tex] \sf = 6\sqrt{3} + 5\sqrt{3} - 7\sqrt{3} [/tex]

[tex] \sf = \red{4\sqrt{3} }[/tex]

[tex] \: [/tex]

No 5.

[tex] \sf 2\sqrt{45} + \sqrt{20} - \sqrt{125}[/tex]

[tex] \sf = 2(3\sqrt{5}) + 2\sqrt{5} - 5\sqrt{5}[/tex]

[tex] \sf = 6\sqrt{5} + 2\sqrt{5} - 5\sqrt{5} [/tex]

[tex] \sf = \red{3\sqrt{5}}[/tex]

[tex] \: [/tex]

No 6.

[tex] \sf ( \frac{1}{16} ) {}^{ - \frac{1}{2} } = ( \frac{1}{ {2}^{2} } ) {}^{ - \frac{1}{2} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf = {2}^{( - 4)} {}^{ - \frac{1}{2} } \\ \sf = {2}^{( \frac{ 4}{2} )} \: \: \: \: \: \: \: \\ \sf = {2}^{2} \: \: \: \: \: \: \: \: \: \: \\ \sf =\red{4} \: \: \: \: \: \: \: \: \: \: \:[/tex]

'비상' (Svt)

Answer 2

Jawaban:

1. √3 x √8 = √24

= √4x6 = 2√6. (A)

2. 2√8 x √3 = 2√24

= 2√4x6 = 2.2√6

= 4√6 (B)

3. √300 ÷√6 = √50 = √25 x2

= 5√2 (A)

4. √108 + √75 - √147 = √36x3 + √25x3 -√49x3

= 6√3 + 5√3 - 7√3

= 4√3 (B)

5. 2√45 + √20 - √125 = 2√9x5 + √4x5 - √25 x 5

= 2.3√5 + 2√5 - 5√5 = 6√5+ 2√5 - 5√5

= 3√5 (B)

6. (1/16)-¹/² = (1/4²) -¹/²

= (1/4)-¹ = 4

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