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3 · ∛3⁻²
=3 · 3^(-2/3)
= 3^(1 - 2/3)
= 3^(3/3 - 2/3)
=3^(1/3)
3a
(∛5²)³
= 5²
= 25
3d
81^(1/4) - 125^(1/3) + 4^(1/2)
= (3^4)^(1/4) - (5^3)^(1/3) + (2^2)^(1/2)
= 3 - 5 + 2
= 0
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