Question

Tolong bantu jawab no brp aja pake cara

Answer 1

DF= diagonal ruang
DF=8√3
misal titik tengah df adlh titik o mka
do = ½ df
do= ½8√3
do=4√3

pnjng dp =√(½ he)² + hd
= √4²+8²
=√16+64
=√80
=4√5

jdi jrk po (titik p ke garis df)
√(4√3)² + (4√5)²
√48+ 80
√128
8√2
jd jrk ttik p k Gris df adlh 8√2