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k[-1 4] × [1 2] = [0 1]
[2k 3k] [4 h] [1 0]
[-k 4k] × [1 2] = [0 1]
8k+3k = 1...(1)
2kh+6k = 0...(2)
-4k+4k = 0...(3)
-kh+8k = 1...(4)
ambil persamaan 1
8k+3k = 1
11k = 1
k = 1/11
ambil persamaan 2
2kh+6k = 0
subtitusi k-nya
2(1/11)h+6(1/11) = 0
(2/11)h+(6/11) = 0
2h+6 = 0
2h = -6
h = -3
berarti (h/k) adalah,
h/k
-3/(1/11)
-3×(11/1)
-3×11
-33
h/k = -33 (A)