1. Subtitusi : t = ∅³+∅
dt = (3∅²+1)d∅
∫(∅³+∅)⁵.(3∅²+1).d∅ = ∫t⁵.dt
= 1/6 . t⁶ + C
= 1/6 . (∅³+∅)⁶ + C
2. 1 - 2sin²(z) = cos(2z)
∫(1-2sin²(z)).sin(2z).dz = ∫(cos(2z).sin(2z)) . dz
= 1/2 . ∫sin(4z) . dz
subtitusi t = 4z, dt = 4.dz => dz = 1/4 . dt
= 1/2 . 1/4.∫sin(t).dt
∫(1-2sin²(z)).sin(2z).dz = -1/8 . cos(4z) + C
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.
1. Subtitusi : t = ∅³+∅
dt = (3∅²+1)d∅
∫(∅³+∅)⁵.(3∅²+1).d∅ = ∫t⁵.dt
= 1/6 . t⁶ + C
= 1/6 . (∅³+∅)⁶ + C
2. 1 - 2sin²(z) = cos(2z)
∫(1-2sin²(z)).sin(2z).dz = ∫(cos(2z).sin(2z)) . dz
= 1/2 . ∫sin(4z) . dz
subtitusi t = 4z, dt = 4.dz => dz = 1/4 . dt
= 1/2 . 1/4.∫sin(t).dt
∫(1-2sin²(z)).sin(2z).dz = -1/8 . cos(4z) + C