Jawaban:
33. C
34. D
35 47 cm2 ( tdk ada jwban yg sesuai)
36. C
Penjelasan dengan langkah-langkah:
33. L = 1/2 × phi x r^2 = 1/2 × 3.14 × 1 = 1.57
34. L =( 1/2 lingkaran besar) - (2x1/2 lingkaran kecil)
= (1/2 x phi x r^2) - (phi × r^2)
= (1/2 × 22/7 × 7 x 7) - (22/7 × 3.5 x 3.5)
= (11 x 7) - (11 × 3.5)
= 11 x 3.5 = 38.5
35. tembereng = (L juring - luas segitiga)
Luas juring = 1/4 × phi x r^2 = 1/4 × 3.14 x 100 = 73.5
luas segitiga = 1/2 × 10^2 = 50
luas tembereng = 23..5
luas 2 tembereng = 47
36. = (1/4 phi ×r^2 )- (1/4 phi xr^2)
= (1/4 × 3.14 x10^2 ) - (1/4 × 22/7 × 7 x 7)
= (1/4 × 314)- (1/4 × 154)
= 1/4 × 160
= 40
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Jawaban:
33. C
34. D
35 47 cm2 ( tdk ada jwban yg sesuai)
36. C
Penjelasan dengan langkah-langkah:
33. L = 1/2 × phi x r^2 = 1/2 × 3.14 × 1 = 1.57
34. L =( 1/2 lingkaran besar) - (2x1/2 lingkaran kecil)
= (1/2 x phi x r^2) - (phi × r^2)
= (1/2 × 22/7 × 7 x 7) - (22/7 × 3.5 x 3.5)
= (11 x 7) - (11 × 3.5)
= 11 x 3.5 = 38.5
35. tembereng = (L juring - luas segitiga)
Luas juring = 1/4 × phi x r^2 = 1/4 × 3.14 x 100 = 73.5
luas segitiga = 1/2 × 10^2 = 50
luas tembereng = 23..5
luas 2 tembereng = 47
36. = (1/4 phi ×r^2 )- (1/4 phi xr^2)
= (1/4 × 3.14 x10^2 ) - (1/4 × 22/7 × 7 x 7)
= (1/4 × 314)- (1/4 × 154)
= 1/4 × 160
= 40