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f(x) = y = ax² + bx + c
xp = 3
-b/2a = 3
-b = 6a
b = -6a
tikor (0,-8)
tipun (3,1)
jadi :
(0,-8) --> c = -8
(3,1) --> 9a + 3b + c = 1
9a + 3b - 8 = 1
9a + 3b = 9
3a + b = 3
3a -6a = 3
-3a = 3
a = -1
b = 3 -3a
b = 3+3
b = 6
jadi f(x) = -x² + 6x -8
y = -x² +6x - 8
motong sumbu y, x = 0
y = -8
berarti melalui titk (0,-8)