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f(2)=13
2a+b=13.............(persamaan 1)
f(5)=22
5a+b=22..............(persamaan 2)
pake cara eliminasi
persamaan 2 - persamaan 1 hasilnya:
--->3a=9
a=3
b=7
f(2) = a(2) + b
13 = 2a + b
f(5) = 22
f(5) = a(5) + b
22 = 5a + b
5a + b = 22
2a + b = 13
(dikurangi)
3a = 9
a = 9/3
a = 3
2a + b = 13
2(3) + b = 13
b = 13-6
b = 7