Jawaban:
Penjelasan dengan langkah-langkah:
Luas Permukaan
(Keliling alas x tinggi)+2(alas persegi panjang+segitiga)
130 cm x 40)+2[(pxl)+2(1/2axt)]
5200 +2[(25×30)+2(1/2.30×20)]
5200 +2[(750)+2(15×20)]
5200 +2[(750)+2(300)]
5200 +[(1500+600)]
5200+ 2100
7300 cm²
Keliling alas
persegi panjang dan segitiga
(2t + l) + (2 s)
(2(25)+30) + (2(25)
(50+30) + (50)
(80)+(50)
130 cm
s=√(1/2p )²+(T-l)²
=√(1/2.30 )²+(45-25)²
=√(15 )²+(20)²
=√(225 )+(400)
=√(625 )
=25
CARA LAIN:
(2(P.T + L.T)+P.L)+(2 (1/2 x a x t) + 2(p x s)]
(2(40.25 + 30.25)+40.30)+(2(1/2.30.20)+2(40.25)
(2(1000+750)+1200)+(2(1/2.600)+2(1000)
(2(1750)+1200)+(2(300)+2(1000)]
(3500+1200)+(600+2000)
(4700)+(2600)
(7300) cm²
⇒ Opsi C.
Demikian
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Verified answer
Jawaban:
BANGUN RUANG
Penjelasan dengan langkah-langkah:
Luas Permukaan
(Keliling alas x tinggi)+2(alas persegi panjang+segitiga)
130 cm x 40)+2[(pxl)+2(1/2axt)]
5200 +2[(25×30)+2(1/2.30×20)]
5200 +2[(750)+2(15×20)]
5200 +2[(750)+2(300)]
5200 +[(1500+600)]
5200+ 2100
7300 cm²
Keliling alas
persegi panjang dan segitiga
(2t + l) + (2 s)
(2(25)+30) + (2(25)
(50+30) + (50)
(80)+(50)
130 cm
s=√(1/2p )²+(T-l)²
=√(1/2.30 )²+(45-25)²
=√(15 )²+(20)²
=√(225 )+(400)
=√(625 )
=25
CARA LAIN:
(2(P.T + L.T)+P.L)+(2 (1/2 x a x t) + 2(p x s)]
(2(40.25 + 30.25)+40.30)+(2(1/2.30.20)+2(40.25)
(2(1000+750)+1200)+(2(1/2.600)+2(1000)
(2(1750)+1200)+(2(300)+2(1000)]
(3500+1200)+(600+2000)
(4700)+(2600)
(7300) cm²
⇒ Opsi C.
Demikian