Materi : Bangun Ruang Sisi Datar
tst¹ = √[ (½AB)² + t² ] = √[ 9² + 12² ] = 15 cm
tst² = √[ (½BC)² + t² ] = √[ 5² + 12² ] = 13 cm
Lp = 2( pt + lt ) + pl + p.tst² + l.tst¹
Lp = 2( 18.8 + 10.8 ) + 18.10 + 18.13 + 10.15
Lp = 2( 144 + 80 ) + 180 + 234 + 150
Lp = 2( 224 ) + 414 + 150
Lp = 448 + 564
Lp = 1.012 cm² { a. }
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[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]
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Materi : Bangun Ruang Sisi Datar
tst¹ = √[ (½AB)² + t² ] = √[ 9² + 12² ] = 15 cm
tst² = √[ (½BC)² + t² ] = √[ 5² + 12² ] = 13 cm
Luas Permukaan Bangun diatas
Lp = 2( pt + lt ) + pl + p.tst² + l.tst¹
Lp = 2( 18.8 + 10.8 ) + 18.10 + 18.13 + 10.15
Lp = 2( 144 + 80 ) + 180 + 234 + 150
Lp = 2( 224 ) + 414 + 150
Lp = 448 + 564
Lp = 1.012 cm² { a. }
Semoga bisa membantu
[tex] \boxed{ \colorbox{darkblue}{ \sf{ \color{lightblue}{ answered\:by\: BLUEBRAXGEOMETRY}}}} [/tex]