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Jika ratio F2 ditambahkan maka totalnya ada 16.....Genotif hterizigot diberi nilai 2 dan homozogot diberi nilai 1....
Genotif RrPp nilainya 2x2 = 4...
Maka genotif utk induk X juga geitifnya sama RrPp dg nilai 2x2= 4...
Jadi yg disilangkan di F1 adalah...
RrPp x RrPp ....2x2x2x2 = 16