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Verified answer
Mata Pelajaran : MatematikaMateri : Pangkat
Diketahui : Gambar
Ditanyakan : Bentuk sederhana
Jawab :
p. (a^2)^4 a^6 / (a^3)^3
= a^(2x4 + 6 - 3x3 )
= a^5
a pangkat 5
q. (7m^2)^3/(7m^4)^2
= 7m^( 2x3 - 4x2)
= 7m^-2 atay 7 / m^-2
7m pangkat negatif dua atau 7 per m pangkat 2
Verified answer
P)[(a^2)^4 . a^6]/(a^3)^3
= [a^8 . a^6]/a^9
= [a^14]/a^9
= a^5
Q)
[(7m^2)^3]/(7m^4)^2
= [7^3 m^6]/[7^2 m^8]
= 7m^(-2)
= 7/m^2