Jawab:
Cara Cepat
6.
f(x) = x²(x + 6)
f'(1) = 3(1) + 12(1) = 15
7.
f(x) = x + 1 / x - 1
f'(x) = (x - 1) - (x + 1) / (x - 1)²
f'(x) = -2 / (x - 1)²
8.
y = (3x² + 1)³
y' = turunkan pangkat luar lalu turunkan pangkat dalam
y' = 3(3x² + 1)² . 6x
y' = 18x(3x² + 1)²
9.
f(x) = 3x² + 4x - 1
f'(m) = 10
m = x
f'(x) = 6x + 4
10 = 6x + 4
6x = 6
x = m = 1
10.
f(x) = 8x - x²
naik berarti f'(x) > 0
f'(x) = 8 - 2x
f'(x) = (4 - x)2
4 - x = 0
x = 4
x > 4
Jadi fungsi naik pada interval x > 4
Koreksi dulu ya...
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Jawab:
Cara Cepat
6.
f(x) = x²(x + 6)
f'(1) = 3(1) + 12(1) = 15
7.
f(x) = x + 1 / x - 1
f'(x) = (x - 1) - (x + 1) / (x - 1)²
f'(x) = -2 / (x - 1)²
8.
y = (3x² + 1)³
y' = turunkan pangkat luar lalu turunkan pangkat dalam
y' = 3(3x² + 1)² . 6x
y' = 18x(3x² + 1)²
9.
f(x) = 3x² + 4x - 1
f'(m) = 10
m = x
f'(x) = 6x + 4
10 = 6x + 4
6x = 6
x = m = 1
10.
f(x) = 8x - x²
naik berarti f'(x) > 0
f'(x) = 8 - 2x
f'(x) = (4 - x)2
4 - x = 0
x = 4
x > 4
Jadi fungsi naik pada interval x > 4
Koreksi dulu ya...