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jadi lim (√3+x - √2x )/ (3-x) . (√3+x + √2x) / (√3+x + √2x) =
lim ( 3+x - 2x ) / (3-x)(√3+x + √2x)
lim (3-x) / (3-x)(√3+x + √2x) = lim 1/ (√ 3+x + √2x) = 1/(2√6) = 1/2 . 1/6√6 = 1/12 (√6)