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Verified answer
Besar sudut pusat = 2 kali sudut keliling∠AOB = 2 ∠ACB
(6x+10)=2(2x+14)
6x+10 = 4x + 28
6x - 4x = 28 - 10
2x = 18
x = 18/2
x = 9°
AOB = 6.9° + 10°= 54° +10° = 64°
2ABO + 64° = 180°
2ABO = 180° - 64°
2ABO = 116°
ABO = 116°/2
ABO = 58°