Question

Tolong bangett ya kakk dibantu beserta caranyaa:))

Answer 1

Penjelasan dengan langkah-langkah:

a.

[tex]2 {}^{x + 1} = 16 \sqrt{2} [/tex]

[tex]2 {}^{x + 1} = 2 {}^{ \frac{9}{2} } [/tex]

[tex]x + 1 = \frac{9}{2} [/tex]

[tex]x = \frac{7}{2} [/tex]

..

b.

[tex]8 \sqrt{2} = 2 {}^{x - 1} [/tex]

[tex]2 {}^{3} \times 2 {}^{ \frac{1}{2} } = 2 {}^{x - 1} [/tex]

[tex]2 {}^{ \frac{7}{2} } = 2 {}^{x - 1} [/tex]

[tex] \frac{7}{2} = x - 1[/tex]

[tex]x = \frac{9}{2} [/tex]