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b. 10log(2.10²)=0log2+10log10²= 0,3010+2=2,3010
c. 10log(2.10³)=10log2+10log10³= 0,3010+3=3,3010
d. 10log(2.10⁴)=10log2+10log10⁴= 0,3010+4=4,3010
4a. 10log2+10log2= 0,3010+0,3010=0,6020
b. 10log2+10log3 = 0,3010+0,4771=0,7781
c. 10log3+10log3 = 0,4771+0,4771=0,9542
d. 10log2²+10log3 = 2(0,3010)+0,4771=0,6020+0,4771=1,0791