Question

Tmn2 tlong jwb no.8b,c,d ya...

Answer 1

8b) log 27 +log 14 - log 9 - log7 - log6
     = log 9 + log 3 + log 2 + log 7 - log 9 - log7 - log3 - log 2=0
8c)2/3(2log8) - 3/2(2log 16) + 1/2(2log32)
    =(2/3)x3(2log2)-(3/2)x4(2log2) +(1/2)x5(2log2)
    = 2.1 - 3.2.1 + (1/2).5.1
    =2-6+(5/2)=-1,5
8d)4log(10/9) - 4log(24/25) - 3(4log(5/6))
    = 4log10 - 4log9 - 4log24 + 4log25 - 3.(4log5) +3(4log6)
    =(1/2)(2log2) + (1/2)(2log5) -(2log3) - (4log4) -(1/2)(2log3) - (1/2)(2log2) + (2log5) -(3/2)(2log5) + (3/2)(2log2) +(3/2)(2log3)
    =(-1) + (3/2)
     =0,5