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3 log 6 = 3 log 2/3
= 3 log 2 - 3 log 3
= 1/ 2log3 - 1
= 1/c - c/c
= (c-1) / c
2. 2log3 =x dan 2log5 = y maka,
10 log 45 = 2log45 / 2log10
= (2log3^2 + 2log5) / 2log5 + 2log2
= (2(2log3) + 2log5) / 2log5 + 1
= (2x+y) / (y+1)
maaf saya cmn bisa bantu itu saja, saya juga msih dlm thap pmblajaran