6] Tabung t = 410 m t = 410 x 1.000 mm t = 410.000 mm
r = d/2 r = 4/2 r = 2 mm
volume = π x r x r x t volume = 3,14 x 2 x 2 x 410.000 volume = 5.149.600 mm^3 volume = 5.149,6 cm^3
berat kawat = 5.149,6 x 6,2 berat kawat = 31.927,52 gram ✩✩ A ✩✩
7] kerucut luas sisi = 1.056 π x r x (r + s) = 1.056 3,14 x 12 x (12 + s) = 1.056 12 + s = 1.056 / (3,14 x 12) s = 28,025 - 12 s = 16,025 cm s = 16,03 cm
Verified answer
Bab Bangun RuangMatematika SMP Kelas VIII
6] Tabung
t = 410 m
t = 410 x 1.000 mm
t = 410.000 mm
r = d/2
r = 4/2
r = 2 mm
volume = π x r x r x t
volume = 3,14 x 2 x 2 x 410.000
volume = 5.149.600 mm^3
volume = 5.149,6 cm^3
berat kawat = 5.149,6 x 6,2
berat kawat = 31.927,52 gram
✩✩ A ✩✩
7] kerucut
luas sisi = 1.056
π x r x (r + s) = 1.056
3,14 x 12 x (12 + s) = 1.056
12 + s = 1.056 / (3,14 x 12)
s = 28,025 - 12
s = 16,025 cm
s = 16,03 cm
✩✩ B ✩✩