Tlong jawab Pr matematika di bwah ! pkai cara !!!"pliss gays !!
subebe
Luas lingkaran = 3,14 x 40 x 40 = 5.024 cm² a. Luas juring AOB = 60/360 x 5.024 cm² = 837,33 cm² b. Luas segitiga = 1/2 sin 60 x 40 x 40 = 1/2 x 1/2√2 x 1600 = 400√2 cm² = 565,69 cm² c. luas tembereng = juring - segitiga = 837,33 - 565,69 =271,64
a. Luas juring AOB = 60/360 x 5.024 cm² = 837,33 cm²
b. Luas segitiga = 1/2 sin 60 x 40 x 40 = 1/2 x 1/2√2 x 1600
= 400√2 cm²
= 565,69 cm²
c. luas tembereng = juring - segitiga
= 837,33 - 565,69
=271,64