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=
=
= 12cm
b. Luas ΔKMN = × a × t
= × 12 × 5
= 30cm²
c. Luas seluruh sisi tegak = (2 × LM × MQ) + ( 2 × KL × PL)
= (2 × 5 × 16) + (2 × 12 × 16 )
= 160 + 384
= 544cm²
= √169 - 25
= √144
= 12 cm
Panjang balok = 4(p + l +t)
= 4(12 + 5 + 16)
= 4(33)
= 132 cm
b. Luas ΔKMN = 1/2 × a × t
= 1/2 × 12 × 5
= 30cm²
c. Luas seluruh sisi tegak = (2 × LM × MQ) + ( 2 × KL × PL)
= (2 × 5 × 16) + (2 × 12 × 16 )
= 160 + 384
= 544 cm²