Question

tlong dijawab pakai jalan kk!!!​

Answer 1

Jawaban:

5 orang merasa terbantu

auratanzila30

Terpelajar

121 jawaban

72.4 rb orang terbantu

Jawaban:

2x + 3y + 3z = 11 ...(1)

x + 4y + z = 7 ...(2)

2x + y + z = 5 ...(3)

eliminasi pers (1) dan (3)

2x + 3y + 3z = 11

2x + y + z = 5

__________ -

2y + 2z = 6 ...(4)

eliminasi pers (2) dan (3)

x + 4y + z = 7 |×2| 2x + 8y + 2z = 14

2x + y + z = 5 |×1| 2x + y + z = 5

_____________ -

7y + z = 9 ...(5)

eliminasi pers (4) dan (5)

2y + 2z = 6 |×1| 2y + 2z = 6

7y + z = 9 |×2| 14y + 2z = 18

__________ -

-12y = -12

y = 1

subs y = 1 ke pers (4)

2y + 2z = 6

2(1) + 2z = 6

2 + 2z = 6

2z = 6 - 2

2z = 4

z = 2

subs y = 1 dan z = 2 ke pers (3)

2x + y + z = 5

2x + 1 + 2 = 5

2x + 3 = 5

2x = 5 - 3

2x = 2

x = 1

jadi, x = 1, y = 1, dan z = 2 maka x + y + z = 1 + 1 + 2 = 4

Penjelasan dengan langkah-langkah:

c. 4

Answer 2

Jawaban:

Jawaban no 14 adalah C.4