Tlong dibantu ya.soal integral batas atas 3 dan batas bawah 2 (x-3) ( x-2) dx .terima kasih
azharhadi
![\int\limits^3_2 { x^{2} -5x+6} \, dx \\ \frac{1}{3} x^3- \frac{5}{2} x^{2} +6x \\ [tex] \frac{3^3}{3} - \frac{5.3^2}{2}+6.3-( \frac{2^3}{3}- \frac{5.2^2}{2}+6.2) \\ \\ \frac{9}{2}- \frac{14}{3} = - \frac{1}{6}](https://tex.z-dn.net/?f=+%5Cint%5Climits%5E3_2+%7B+x%5E%7B2%7D+-5x%2B6%7D+%5C%2C+dx++%5C%5C++%5Cfrac%7B1%7D%7B3%7D+x%5E3-+%5Cfrac%7B5%7D%7B2%7D+x%5E%7B2%7D+%2B6x+%5C%5C+%5Btex%5D+%5Cfrac%7B3%5E3%7D%7B3%7D+-+%5Cfrac%7B5.3%5E2%7D%7B2%7D%2B6.3-%28+%5Cfrac%7B2%5E3%7D%7B3%7D-+%5Cfrac%7B5.2%5E2%7D%7B2%7D%2B6.2%29+%5C%5C++%5C%5C++%5Cfrac%7B9%7D%7B2%7D-+%5Cfrac%7B14%7D%7B3%7D+%3D+-+%5Cfrac%7B1%7D%7B6%7D+++++ "\int\limits^3_2 { x^{2} -5x+6} \, dx \\ \frac{1}{3} x^3- \frac{5}{2} x^{2} +6x \\ [tex] \frac{3^3}{3} - \frac{5.3^2}{2}+6.3-( \frac{2^3}{3}- \frac{5.2^2}{2}+6.2) \\ \\ \frac{9}{2}- \frac{14}{3} = - \frac{1}{6}")
2 votes
Thanks 1
linne
ga ada. di pg 5/6
azharhadi
sudah saya tulis lengkap... tadi salah hitung :D
linne
-1/6 ya?
azharhadi
ya
linne
mksih
linne
saya mau tanya ni.integral (x + 3 cos x ) dx