Question

Tlong dbantu....
Aturan bilangan oksidasi
1. PO3³-
2. Cr2O4²-

Answer 1

1. PO₃³⁻, biloks O = -2 maka biloks p
-3 = 3(-2) + k
-3 = (-6) + k
-3+ 6 =k
k = +3

Biloks p =+3

2. Biloks O = -2
Maka
2Cr + 4(-2) = -2

2Cr -8 = -2

2Cr= 6

Cr = +3