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Kelas 8 MatematikaBab Operasi Aljabar dan Fungsi
10]
(i) 4x² - 9 = (2x + 3) (2x - 3)
4x² - 9 = 4x² - 6x + 6x - 9
4x² - 9 = 4x² - 9 (benar)
(ii) 2x² + x - 3 = (2x - 3) (x + 1)
2x² + x - 3 = 2x² + 2x - 3x - 3
2x² + x - 3 = 2x² - x - 3 (salah)
(iii) x² + x - 6 = (x + 3) (x - 2)
x² + x - 6 = x² - 2x + 3x - 6
x² + x - 6 = x² + x - 6 (benar)
i dan iii
✩✩ C ✩✩
11] Syarat fungsi, domain hanya dimasukkan 1 kali
1] (1, a), (2, a), (3, a), (4, a) → fungsi
Domain = { 1, 2, 3, 4 }
2] (a, 1), (b, 1), (c, 1), (d, 1) → fungsi
Domain = { a, b, c, d }
1 dan 2
✩✩ A ✩✩
1.) 4x"-9 = (2x+3)(2x-3)
4x"-9 = (4x"-6x+6x-9)
4x"-9 = 4x"-9 (benar)
2.) 2x"+x -3 = (2x-3)(x+1)
2x"+x -3 = (2x"+2x-3x-3)
2x"+x -3 = 2x"-x-3 (salah)
3.) x"+x -6 = (x+3)(x-2)
x"+x -6 = (x"-2x+3x-6)
x"+x -6 = x"+x -6 (benar)
4.) x"+4x-5 = (x-5)(x+1)
x"+4x-5 = (x"+x-5x-5)
x"+4x-5 = x"-4x-5 (salah)
( " = pangkat 2)
Jwb 1 dan 3 (c)
11.) fungsi = jawabannya boleh bercabang
Jd jwb = A. 1 dan 2
Maaf kalau salah, semoga membantu