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R1 = 10 cm
R2 = 5 cm
PQ = 8 cm
AB?
PQ^2 = AB^2 - (R1 + R2)^2
8^2 = AB^2 - (10 + 5)^2
64 = AB^2 - 15^2
AB^2 = 64 + 225
AB = √289
AB = 17
Jarak titik pusat kedua lingkaran adalah 17 cm