tanC = de/sa = √6/3
maka
de= √6
sa= 3
mi= √(3²+(√6)²) = √(9+6) = √15
cosC = sa/mi = 3/√15 = 3/15 √15
c² = a²+b²+2abcosC
c² = (2√5)²+(5√3)²+2(2√5)(5√3)(3/15 √15)
c² = 20+75+20√15. 3/15 √15
c² = 20+75+60/15 . 15
c² = 20+75+60
c² = 155
c = √155
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tanC = de/sa = √6/3
maka
de= √6
sa= 3
mi= √(3²+(√6)²) = √(9+6) = √15
cosC = sa/mi = 3/√15 = 3/15 √15
c² = a²+b²+2abcosC
c² = (2√5)²+(5√3)²+2(2√5)(5√3)(3/15 √15)
c² = 20+75+20√15. 3/15 √15
c² = 20+75+60/15 . 15
c² = 20+75+60
c² = 155
c = √155