Titik p P(-2,5), Q(2,-3) dan R(x,9) terletak pada satu garis lurus. Nilai x adalah
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Verified answer
Q-P=k(R-Q)(2+2,-3-5)=(x-2,9+3)
(4,-8)=k(x-2,12)
(4,-8)=(k(x-2),12k)
12k=-8
k=-8/12=-2/3
4=k(x-2)
4=-2/3 (x-2)
3*4=-2(x-2)
12=-2x+4
2x=4-12
2x=-8
x=-8/2
=-4