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f '(x) = 3x² - 6x - 9 = 0
3(x² - 2x - 3) = 0
3(x - 3)(x + 1) = 0
x = 3 atau x = -1
x = -1 maka f(x) = -1 -3 + 9 = 5
jadi, titik balik maksimumnyanya (-1, 5)