Question

Titik balik grafik fungsi kuadrat y= f(x) =2x²-4x+5

Answer 1

Verified answer

F(x)= 2x²-4x+5

titik balik didapat dari f'(x)=0
f'(x)=4x-4 =0
4x=4
x=1

y= 2x²-4x+5
y= 2(1)²-4(1)+5
y= 2-4+5
y= 3

jadi titik balik nya
(1,3)