subebe
A. kita misalkan adala 2 bangun di alas Luas alas = 60 x 18 + (60-52) x (38-18) = 1.080 + (8 x 20) = 1.080 + 160 = 1.240 cm² Keliling alas = 18 + 60 + 38 + (60-52) + (38-18) + 52 = 196 Luas sisi tegak prisma = keliling x tinggi = 196 x 38 = 7.448 cm² Seng yang dibutuhkan = 7.448 + 1.240 = 8.688 cm² b. Volume = L alas x tinggi = 1.240 x 38 = 47.120 cm³
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subebe
A. kita misalkan adala 2 bangun di alas Luas alas = 60 x 18 + (60-52) x (38-18) = 1.080 + (8 x 20) = 1.080 + 160 = 1.240 cm² Keliling alas = 18 + 60 + 38 + (60-52) + (38-18) + 52 = 196 Luas sisi tegak prisma = keliling x tinggi = 196 x 38 = 7.448 cm² Seng yang dibutuhkan = 7.448 + 1.240 = 8.688 cm² b. Volume = L alas x tinggi = 1.240 x 38 = 47.120 cm³
Luas alas = 60 x 18 + (60-52) x (38-18)
= 1.080 + (8 x 20)
= 1.080 + 160
= 1.240 cm²
Keliling alas = 18 + 60 + 38 + (60-52) + (38-18) + 52 = 196
Luas sisi tegak prisma = keliling x tinggi
= 196 x 38 = 7.448 cm²
Seng yang dibutuhkan = 7.448 + 1.240 = 8.688 cm²
b. Volume = L alas x tinggi = 1.240 x 38 = 47.120 cm³
Luas alas = 60 x 18 + (60-52) x (38-18)
= 1.080 + (8 x 20)
= 1.080 + 160
= 1.240 cm²
Keliling alas = 18 + 60 + 38 + (60-52) + (38-18) + 52 = 196
Luas sisi tegak prisma = keliling x tinggi
= 196 x 38 = 7.448 cm²
Seng yang dibutuhkan = 7.448 + 1.240 = 8.688 cm²
b. Volume = L alas x tinggi = 1.240 x 38 = 47.120 cm³