Question

Tinggi tabung 8cm , luas selimut 352 cm (persergi) , berapakah diameter dan jari jari tabung ? tolong dibantu ya

Answer 1

L selimut tabung = 352
2.phi.r.t = 352
2.22/7.r.8 = 352
352.r = 352 . 7
352.r = 2464
r = 2464/352
r = 7 cm

maka :

d = 2.r = 2.7 = 14 cm

Answer 2

T= 8 cm
Ls = 352 cm2
Ls = keliling alas * t
352= 22/7*d*t
352= 22/7*d*8
352*7=22*8*d
2464= 176*d
d = 2464/176
d(diameter)= 14 cm
jari" = 7 cm
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