Question

Tiga mata logam dilambungkan 180 kali berapakah frekuensi harapan munculnya 1 angka 2 gambar?

Answer 1

Dik :
n = 180x
n(s) 3 mata logam = 8 
n(a) 1 angka 2 gambar = 3
Dit : fn
Jawab :
#cari p(A) = n(a)/n(s) = 3/8

fn = nxp(A) = 180 x 3/8 = 67,5 :)