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1 3 3 1 -> untuk kasus n = 3
menunjukkan -> AAA, AAG, AGA, GAA, GGA, GAG, AGG, GGG
n(S) = 8
a) n(2A,1G) = 3
maka P(2A, 1G) = n(2A, 1G) / n(S) = 3/8
b) n(1A, 2G) = 3
maka P(1A, 2G) = n(1A, 2G) / n(S) = 3/8