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C₁=2μF=2.10⁻⁶F
C₂=3μF=3.10⁻⁶F
C₃=6μF=6.10⁻⁶F
Ditanyakan: Cp?
Dijawab:
Cp=C₁+C₂+C₃
=(2+3+6).10⁻⁶
=11.10⁻⁶ F atau 11μF
#Jika ini penting bagi anda maka jadikan jawaban terbaik,tapi jika tidak penting abaikan saja.